ElasticSearch java API - 聚合查询
以球员信息为例,player索引的player type包含5个字段,姓名,年龄,薪水,球队,场上位置。 index的mapping为: 首先,初始化Builder:
"mappings": { "player": { "properties": { "name": { "index": "not_analyzed", "type": "string" }, "age": { "type": "integer" }, "salary": { "type": "integer" }, "team": { "index": "not_analyzed", "type": "string" }, "position": { "index": "not_analyzed", "type": "string" } }, "_all": { "enabled": false } } }索引中的全部数据:
SearchRequestBuilder sbuilder = client.prepareSearch("player").setTypes("player");接下来举例说明各种聚合操作的实现方法,因为在es的api中,多字段上的聚合操作需要用到子聚合(subAggregation),初学者可能找不到方法(网上资料比较少,笔者在这个问题上折腾了两天,最后度了源码才彻底搞清楚T_T),后边会特意说明多字段聚合的实现方法。另外,聚合后的排序也会单独说明。
- group by/count
select team, count(*) as player_count from player group by team;ES的java api:
TermsBuilder teamAgg= AggregationBuilders.terms("player_count ").field("team");sbuilder.addAggregation(teamAgg);SearchResponse response = sbuilder.execute().actionGet();
- group by多个field
select team, position, count(*) as pos_count from player group by team, position;ES的java api:
TermsBuilder teamAgg= AggregationBuilders.terms("player_count ").field("team");TermsBuilder posAgg= AggregationBuilders.terms("pos_count").field("position");sbuilder.addAggregation(teamAgg.subAggregation(posAgg));SearchResponse response = sbuilder.execute().actionGet();
- max/min/sum/avg
select team, max(age) as max_age from player group by team;ES的java api:
TermsBuilder teamAgg= AggregationBuilders.terms("player_count ").field("team");MaxBuilder ageAgg= AggregationBuilders.max("max_age").field("age");sbuilder.addAggregation(teamAgg.subAggregation(ageAgg));SearchResponse response = sbuilder.execute().actionGet();
- 对多个field求max/min/sum/avg
select team, avg(age)as avg_age, sum(salary) as total_salary from player group by team;ES的java api:
TermsBuilder teamAgg= AggregationBuilders.terms("team");AvgBuilder ageAgg= AggregationBuilders.avg("avg_age").field("age");SumBuilder salaryAgg= AggregationBuilders.avg("total_salary ").field("salary"); sbuilder.addAggregation(teamAgg.subAggregation(ageAgg).subAggregation(salaryAgg)); SearchResponse response = sbuilder.execute().actionGet();
- 聚合后对Aggregation结果排序
select team, sum(salary) as total_salary from player group by team order by total_salary desc;ES的java api:
TermsBuilder teamAgg= AggregationBuilders.terms("team").order(Order.aggregation("total_salary ", false);SumBuilder salaryAgg= AggregationBuilders.avg("total_salary ").field("salary"); sbuilder.addAggregation(teamAgg.subAggregation(salaryAgg)); SearchResponse response = sbuilder.execute().actionGet();需要特别注意的是,排序是在TermAggregation处执行的,Order.aggregation函数的第一个参数是aggregation的名字,第二个参数是boolean型,true表示正序,false表示倒序。
- Aggregation结果条数的问题
TermsBuilder teamAgg= AggregationBuilders.terms("team").size(15);
- Aggregation结果的解析/输出
MapaggMap = response.getAggregations().asMap();StringTerms teamAgg= (StringTerms) aggMap.get("keywordAgg");Iterator teamBucketIt = teamAgg.getBuckets().iterator();while (teamBucketIt .hasNext()) {Bucket buck = teamBucketIt .next();//球队名String team = buck.getKey();//记录数 long count = buck.getDocCount(); //得到所有子聚合 Map subaggmap = buck.getAggregations().asMap(); //avg值获取方法 double avg_age= ((InternalAvg) subaggmap.get("avg_age")).getValue(); //sum值获取方法 double total_salary = ((InternalSum) subaggmap.get("total_salary")).getValue(); //... //max/min以此类推 }
- 总结